Question

Solve the pair of linear equation.

Answer 1

bx-ay/ab=0
bx=ay
 From this x=ay/b;y=bx/a;y/b=x/a
a(ay/b) + b(bx/a)=a² + b²
a²(y/b)+ b²(x/a) -a² - b² =0
a²(y/b -1) + b²(x/a -1)=0
(x/a-1)(a² + b²)=0
x/a=1
x=a ... similarly y=b

Answer 2

HEYA!!!

YOUR SOLUTION IS IN ATTACHMENT.

#KEVIN
HOPE IT HELPS YOU^_^