Question

solve the pair of linear equation 3x+4y=10 and 2x-2y=2 by cross miltiplication method

Answer 1

Hi there !!

First convert in the form of ax^2+bx +c

$3x + 4y - 10 = 0 \\ \\ 2x - 2y - 2 = 0$
x

4 -10
-2 -2

y

-10 3
-2 2

1
3 4
2 -2( cross multiple the nos.)

$we \: get \: \\ \\ \\ \frac{x}{ - 8 - 20} = \frac{y}{ - 20 + 6} = \frac{1}{ - 6 - 8} \\ \\ \\ \frac{x}{ - 28} = \frac{y}{ - 14} = \frac{1}{ - 14} \\ \\ \\ so \: \frac{x}{ - 28} = \frac{1}{ - 14} \: \: x = 2 \\ \\ \\ and y = 1$

Thanks !