Question

Solve the pair of linear equation by elimination method :

4x–19y+13= 0

13x–23y= –19

Answer 1

The given equations are

4x - 19y = - 13 ...(i)

13x - 23y = - 19 ..(ii)

Now, multiplying (i) by 13 and (ii) by 4, we get

52x - 247y = - 169

52x - 92y = - 76

On subtraction, we get

155y = 93

or, y = 3/5

Now, putting y = 3/5 in (i), we get

4x - 19 (3/5) = - 13

or, 4x = - 13 + 57/5

or, 4x = (- 65 + 57)/5

or, 4x = - 8/5

or, x = - 2/5

Therefore, the required solution be

x = - 2/5 and y = 3/5