Question

Solve the pair of linear equation of substitution method 2x-3y=19 and 3x-2y=21

Answer 1

Answer:

x=5

y=-3

Step-by-step explanation:

see attachement

Answer 2

Answer:

=> The value of x = 5, and y = -3.

Step-by-step explanation:

Given that:-

$2x-3y=19$          $...(1)$

$3x-2y=21$          $...(2)$

By substitution method,

We will substitute the value of y from equation ( $1$ ) in equation ( 2 ),

∴ From the first equation,  $y= \frac{(2x-19)}{3}$

So by substituting the value of y in the second equation,

The second equation becomes:  

$=> 3x-\frac{2(2x-19)}{3}=21$

By further simplifying, we get

$=> \frac{9x-4x+38}{3}=21$

$=> 5x=63-38$

$=> 5x=25$

Divide by $5$, on both sides we get

=> $x=5$

So, the value of x is 5.

Substituting the value of x in equation number ( 1 ) we get,

$=>2(5)-3y=19$

$=>10-19=3y$

$=> -9=3y$

$=> y=-3$

So, the value of y is -3.