Question

Solve the pair of linear equations 2x + 3y = 8 and x + 3y = 7 by elimination method.

Answer 1

Step-by-step explanation:

From the second equation, substitute x = 7 - 3y in the first equation.

So,

2(7-3y) + 3y = 8

14-6y + 3y = 8

This on further simplification gives, 3y = 6

Therefore y=2

Re substitute y=2 in x = 7 - 3y

So, we get x as, x = 1

So, the solution is, x = 1 and y = 2

Answer 2

Answer:

Step-by-step explanation:

Given

$\textsf{2x + 3y = 8 ---------------(1)}\\\textsf{x + 3y = 7-------------------(2)}\\\textsf{We will use substitution Method to solve this}\\\\\huge\textbf{But how?}$

In Equation (2)

x + 3y = 7

x = 7- 3y

Now placing it in Equation (1)

2(7-3y)+3y = 8

14 - 6y +3y = 8

14 - 3y = 8

- 3y = -6

y = -6/-3

y = 2

Now placing y as 2 in Equation (2),

x + 3*2 = 7

x + 6 = 7

x = 1

What is Substitution Method?

The process in which we find the first value with respect to second value is Substitution method.

STEPS:-

1. Find x with respect to y
2. Place it in second equation
3. Find y
4. Now place y in 1st equation
5. Find x.

ELIMINATION METHOD:-

This is another convenient method. Just subtract or add the equation to get one value cancelled and find another value and then put the number in the equation to get the cancelled value.