Question

Solve the pair of linear equations: 3x + 2y – 11 = 0, 2x – 3y + 10 = 0 , by Substitution Or Elimination.​

Answer 1

Answer:

$3x + 2y - 11 = 0..........1 \\ 2x - 3y + 10 = 0.........2 \\ in \: e - 1 \\ 3x + 2y - 11 = 0 \\ 3x = 11 - 2y \\ x = \frac{11 - 2y}{3} .........3\\ putting \: the \: value \: of \: x \: in \: e - 2 \\ 2x - 3y + 10 = 0 \\ 2( \frac{11 - 2y}{3} ) - 3y = - 10 \\ \frac{22 - 4y - 9y}{3} = - 10 \\ 22 - 13y = - 30 \\ - 13y = - 30 - 22 \\ 13y = 52 \\ y = 3 \\ putting \: the \: valueof \: y \: in \: e - 1 \\ 3x + 2 \times 3 - 11 = 0 \\ 3x - 5 = 0 \\ x = \frac{5}{</p><p>3}$

Answer 2

No need to worry, Ayush will be offline for a small period.

I can think only of one word that they are "Unstable".

-J73