Solve the pair of linear equations: 3x + 2y – 11 = 0, 2x – 3y + 10 = 0 , by Substitution Or Elimination.
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Elimination method:
Given Equation is 3x + 2y = 11 ----- (1)
Given Equation is 2x - 3y = - 10 ---- (2)
On solving (1) * 2 & (2) * 3, we get
⇒ 6x + 4y = 22
⇒ 6x - 9y = -30
-------------------
13y = 52
y = 4.
Substitute y = 4 in (1), we get
⇒ 3x + 2y = 11
⇒ 3x + 2(4) = 11
⇒ 3x = 11 - 8
⇒ 3x = 3
⇒ x = 1.
Therefore, the value of x = 1 and y = 4.
Hope it helps!
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