solve the pair of linear equations by substitution method x+y=6,x-y=2
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This is the solution by substitution
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x+y=6.......eq.1
x-y=2........ eq.2
x+y=6
= x=6-y..... eq.3
put equation 3 in equation 2
x-y=2
=6-y-y=2
=6-2y=2
=-2y= -4
=y=-4/-2
y=2
put y =2 in equation 3
x=6-y
x=6-2
x=4
_________
x=4
y=2
hope it helps you
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x-y=2........ eq.2
x+y=6
= x=6-y..... eq.3
put equation 3 in equation 2
x-y=2
=6-y-y=2
=6-2y=2
=-2y= -4
=y=-4/-2
y=2
put y =2 in equation 3
x=6-y
x=6-2
x=4
_________
x=4
y=2
hope it helps you
please mark my answer as brainliest
and start following me :)
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