Question

solve the pair of linear equations graphically x-y-1=0, 3x+y-11=0​

Answer 1

Step-by-step explanation:

the given system of equation is 3x+y-11=0

x-y-1=0

now,

3x+y-11=0

y=11-3x

when x=0,we have y=11-3×0=11

when x=3,we have y=11-3×3=2

we have

x-y-1=0

x-1=y

y=x-1

when x=0,we have

y=0-1=-1

when x=3,we have

y=3-1=2

Answer 2

$\small\mathcal\color {Orange}☆Given☆$

(a) ${3x+y-11=0}$

$3x + y - 11 = 0$

$y = - 3x + 11$

$\small\mathcal\color {blue}☆Finding\:x\:and\:y☆$

》When, ${x=2}$

$y = - 3x + 11$

$y = - 3 \times 2 + 11$

$y = 5$

》When, ${x=3}$

$y = - 3x + 11$

$y = -3 \times 3 + 11$

$y = - 9 + 11$

$y = 2$

● Plotting, the points A =(2,5) and B =(3,2) on the graph and drawing lines by joining between them we get, the graph of the equation ${3x+y-11=0}$

$\small\mathcal\color {red}☆Given☆$

(b) ${x-y-1=0}$

$x - y - 1 = 0$

$y = x - 1$

$\small\mathcal\color {green}☆Finding\:x\:and\:y☆$

》 When, ${x=-1}$

$y = x - 1$

$y = - 1 - 1$

$y = - 2$

》When, ${x=3}$

$y = x - 1$

$y = 3 - 1$

$y = 2$

● Plotting, the points R =(-1,-2) and S = (3,2) on the graph and drawing lines joining between them we get, the graph of the equation x-y-1=0

$\huge\mathfrak {Hope\:it\:Helps\:You}$