Question

Solve the pair of linear equations x-y=28 and x–3y=0 and if the solution satisfies,y=mx+5, then find m.

Answer 1

X-y = 28.
X-y -28 = 0 (1)
X-3y = 0.
X-3y = 0 (2)
By elimination method
Subtract (1) from (2) equation
X-3y = 0
- (X-y-28)= 0
Then
X-3y = 0
-X+y+28=0
=. -2y+28=0
-2y = -28
y = 14
Put yvalue in equation 1
X-14-28 =0
X-42 =0
X=42
Put x and y value in y = mx + 5
14=42m+5
14-5=42m
9=42m
9/42=m
3/14=m

Answer 2

Answer :

The given equations are

x - y = 28 ...(i)

x - 3y = 0 ...(ii)

On subtraction, we get

2y = 28

or, y = 14

Putting y = 14 in (ii), we get

x = 3 (14) = 42

Therefore, the required solution be

x = 42, y = 14

Now, putting x = 42 and y = 14 in y = mx + 5, we get

14 = 42m + 5

or, 42m = 9

or, m = 9/42

or, m = 3/14

Therefore, the value of m is 3/14

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