Question

solve the pairs of equation simultaneously 2x - 3y = 17, x² +2y² - 3x + y = 19​

Answer 1

Answer:

Step-by-step explanation:

2x=3y+17

x=(3/2)y+8.5

(9/4)y^2+25.5y+72.25+2y^2-4.5y-25.5+y=19

4.25y^2+22y+27.75y=0

17y^2+88y+111=0

y=(1/34)(-88+/- sqrt (88^2-4(17*111)); sqrt term= sqrt(196)=14

y=-74/34 or -2.18

2x+6.54=17 and x=5.23

substitute into second and 27.35+9.51-15.69-2.18=18.99, checks given rounding error.

exact values are

2x+111/17=289/17

x=89/17, y=-89/17,

(89/17, -37/17)

y=-102/34 or -3

y=-3 and 2x+9=17 and x=4

substitute into second equation and 16+18-12-3=19

(4, -3)

Answer 2

Answer:

Idk the answer bro/sis sry

Step-by-step explanation: