Question

Solve the pairs of linear equations by substitution method 2x + 3y = 20, 3x + 4y = 25​

Answer 1

Step-by-step explanation:

2x+3y = 20 (take as 1st equation)

next equation formation ,

3x+4y = 25

x = (25-4y)/3 (2nd equation)

substitute 2nd equation in 1st equation

2x+3y =20

2 (25-4y)/3+3y = 20

50-4y+3y = 60

50-y =60

y = -10

substitute in 2nd equation

x = 25-4y/3

x = 25+40/3

x= 65/3

x= 21.6