Question

solve the
pairs of linear
equations
by substitution
method 2x+3y= 20,3 x + 4y = 25​

Answer 1

your answer is

x = -5

y = 10

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Answer 2

2x+3y=20 (take as 1st equation)

next equation formation

3x+4y=25

x=(25-4y) /3 (2nd equation substitute 2nd equation in 1st equation)

2x+3y=20

2(25-4y)/3+3y=20

50-4y+3y=60

50-y=60

y=-10

substitute in 2nd equation

x=25-4y/3

x=25+40/3

x=65/3

x=21.6..

I hope this ans helps u......