Question

Solve the problem 3/x+y+2/x-y=3;2/x+y+3/x-y=11/3

Answer 1

Answer:

Step-by-step explanation:

let $\frac{1}{x+y}$ = A and $\frac{1}{x-y}$ = B

therefore ,

3A + 2B = 3 ....... (1)

2A + 3B = 11/3 ......... (2)

(1) * 2 and (2) * 3

6A + 4B = 6 ......... (3)

6A + 9B = 11 .......... (4)

--> (4) - (3),

5B = 5

B = 1

--> put B in (1),

3A = 3 - 2

A = $\frac{1}{3}$

--> A = $\frac{1}{3}$

    $\frac{1}{x+y}$ = $\frac{1}{3}$

    x+y = 3 ........ (5)

--> B = 1

    $\frac{1}{x-y}$ = 1

   x-y = 1 ...........(6)

-->(5) + (6),

2x = 4

x = 2

--> put x in (5),

y = 1

Answer 2

Answer:

Step-by-step explanation: