solve the problem....
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#AlexaRousey here!!
In triangle ABC;
=) angle B + angle A + angle C = 180°
=) angle B + 90° + angle C = 180°
=) angle B + angle C = 180°-90°
=) angle C = 90° - angle B
In triangle ABL;
=) angle B + angle BAL + 90° = 180°
=) angle B + angleBAL = 90°
=) angle BAL = 90° - angle B
By eq 1 & 2;
=) angle C = angle BAL
Hence angle BAL = angle ACB.
Thanks!!
In triangle ABC;
=) angle B + angle A + angle C = 180°
=) angle B + 90° + angle C = 180°
=) angle B + angle C = 180°-90°
=) angle C = 90° - angle B
In triangle ABL;
=) angle B + angle BAL + 90° = 180°
=) angle B + angleBAL = 90°
=) angle BAL = 90° - angle B
By eq 1 & 2;
=) angle C = angle BAL
Hence angle BAL = angle ACB.
Thanks!!
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