Question

solve the problem 8 - c d e please sovle it

Answer 1

$here \: is \: ur \: answer........ \\ \\ (c) \: \frac{x}{6} - \frac{x}{5} = \frac{x}{15} - \frac{x}{3} + 7 \\.. \frac{x}{15} - \frac{x}{3} - \frac{x}{6} + \frac{x}{5} + 7 = 0 \\.. \: \frac{4x - 20x - 10x + 12x + 420}{60} = 0 \\ .. - 14x + 420 = 0 \\ ..14x = 420 \\ ..x = \frac{420}{14} \\ ..x = 30 \\ \\ (d) \: \frac{4x - 5}{7} - \frac{2x + 1}{2} 16x= \frac{1}{2} - x \\ .. \frac{2(4x - 5) - 7(2x + 1)}{14} = \frac{1 - 2x}{2} \\ ..4(4x - 5) - 14(2x + 1) = 14(1 - 2x) \\ ..16x - 20 - 28x - 14 = 14 - 28x \\ ..16x - 28x + 28x = 14 + 14 + 20 \\ ..16x = 48 \\ ..x = 3 \\ \\ (e) \frac{y - 1}{3} - \frac{y - 2}{4} = 1 \\ .. \frac{4(y - 1) - 3(y - 2)}{12} = 1 \\ ..4y - 4 - 3y + 6 = 12 \\ ..y - 2 = 12 \\ ..y = 14$
hope this helps......