Question

Solve the problem..........
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Answer 1

Answer:-

A = 45° and

B = 15°

Step by step explanation

Given

Tan ( A + B ) = √3

=> Tan ( A + B ) = Tan60°

=> A + B = 60° ----- ( 1 )

And

Tan ( A - B ) = 1 / √3

=> Tan ( A - B ) = Tan30°

=> A - B = 30° -------- ( 2 )

Now,

Add ( 1 ) and ( 2 )

A + B = 60°

A - B = 30°

____________

=> 2A = 90°

=> A = 90 / 2

=> A = 45°

Put A = 45° in ( 1 )

A + B = 60°

=> 45° + B = 60°

=> B = 60° - 45°

=> B = 15°

Therefore, A = 45° and B = 15°.

Hope it helps!

Answer 2

Answer:

Given that

Tan ( A + B ) = √3

Tan ( A - B ) = 1/√3

Tan ( A + B ) = √3

Tan ( A + B ) = Tan 60°

A + B = 60° ===> eqn 1

Tan ( A - B ) = 1/√3

Tan ( A - B ) = Tan 30°

A - B = 30° ===> eqn 2

Add eqn 1 and 2 on either sides

A + B = 60°

A - B = 30°

____________

2A ===> 90°

A = 90 / 2

A = 45°

Put "A" value in eqn 1

eqn 1 ==> A + B = 60°

===> 45° + B = 60°

===> B = 60° - 45°

===> B = 15°

Step-by-step explanation:

A = 45°

B = 15°