Question

solve the problem for this question​

Answer 1

Answer:

₹ 250, ₹ 4

Step-by-step explanation:

Let the fixed charge be ₹ x. & the charge per km be ₹ y.

A.T.Q.

x + 110y = 690. --------(1)

x + 200y = 1050. ---------(2)

Subtracting equ.1 from 2

x + 200y - (x + 110y) = 1050 - 690

x + 200y - x - 110y = 360

90y = 360

y = ₹ 4

Putting the value of y in equ.2

x + 200(4) = 1050

x + 800 = 1050

x = 1050 - 800

x = ₹ 250

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