solve the problem in attachment
Attachments:
Answers
Answered by
1
Edge of cubical tank = 1.5 m => 150cm.
Surface area of the tank = 5× 150×150 cm ^2.
AREA OF EACH SQUARE TILE = SIDE×SIDE =25×25.
NO OF TILES REQUIRED = SURFACE AREA OF THE TANK / AREA OF EACH TILE.
5×150×150 / 25×25.
=> 180 <=
COST OF 12 TILES = ₹ 360.
COST OF 1 TILE = ₹ 360 / 12 .
=> ₹30.
THE COST OF 180 TILES => 180 × ₹ 30 = ₹ 5400.
♥️ THANKS ..♥️
Answered by
0
I had the same textbook when I was studying in class IX. This chapter's Surface Areas and Volumes, isn't it ?
Solution:
The side of the cube = 1.5 m = 150 cm
Since he's getting the outer surface of the cube, excluding the base and including the lid, for decor purposes(since he's getting the outer lid tiled).
Area required for tiling = LSA of the cube + Area of one side
=> 4a²+a²=>5a²
=>(5×150²) cm²
Area of each square tile = (25×25)cm²
No. of tiles required= (5×150×150)/25×25
=> 180 tiles
Rate= Rs.360/12 tiles
Total cost = 180×(360)/12= 180×30
=>Rs. 5400/-
Mark it as the brainliest!!
:)
Similar questions
Social Sciences,
7 months ago
English,
7 months ago
Physics,
1 year ago
Physics,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago