Question

solve the problem please​

Answer 1

Solution:-

Given :- PQ = SR & PQ || SR

To Prove:- ∆ PSR ~ ∆RQP

To Proof :-

In ∆PSR & ∆RQP

• PQ = SR ( Given)
• PQ || SR ( Given)
• PR = PR ( Common)

By SSS( Side Side Side) Congruency Rule

=> ∆PSR ~ ∆RQP

By CPCT ( Corresponding Parts Of Congruent Triangles)

• PS = QR

Hence Proved

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