solve the problem,
Questions no. 7
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amitkumar84:
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Answers
Answered by
0
Answer:
(x+1) = 1806
a quadratic equation
x^2 + x - 1806 = 0
factors to
(x+43)(x-42) = 0
positive solution
x = 42 & 43 are the page
hope it helps you
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Answered by
0
Let the two pages be x and x+1
ATQ :-
x+x+1=85
2x=84
PAGES ARE 42&43
IF SUM IS NOT GIVEN AND PRODUCT IS GIVEN :-
x(x+1)=1806
x^2+x -1806=0
By spilliting the middle terms
x^2 +43x-42x-1806 =0
x(x+43)-42(x+43) =0
(x+43)(x-42)=0
x=42
So the pages are 42 ans 43
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➡️Hope it helps
ATQ :-
x+x+1=85
2x=84
PAGES ARE 42&43
IF SUM IS NOT GIVEN AND PRODUCT IS GIVEN :-
x(x+1)=1806
x^2+x -1806=0
By spilliting the middle terms
x^2 +43x-42x-1806 =0
x(x+43)-42(x+43) =0
(x+43)(x-42)=0
x=42
So the pages are 42 ans 43
➡️ Follow me....
➡️Hope it helps
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