Question

SOLVE THE PUZZLE
BA
MULTIPLY B3
-----------
57A

Answer 1

Given BA*B3=57A

taking common as B from given equation then B(3A)=57A

then B=57A/3A=19

Hence B=19

By substituting the value of B in given equation you will get the value of A is 1

Hence A=1,B=19

Verify it if you want.

Answer 2

Answer:

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