solve the quadratic equation 3√2x^2-5x-√2=0
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3√2x²-5x-√2=0
3√2x²-(6-1)x -√2 = 0
3√2x²- 6x + x-√2=0
3√2x(x-√2)+1(x-√2) = 0
(x-√2)(3√2x+1) = 0
.•. x=√2 or x = -1/3√2
so the roots are √2 & -1/3√2.
Later you can rationalize -1/3√2.
hope u like my answer.
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