Math, asked by adithya2611, 1 year ago

solve the quadratic equation 3xsquare -8x-3=0​

Answers

Answered by yadlaramesh
2

Answer:

3x^2-8x-3=0

3x^2-9x+x-3=0        (here quadratic so 3x^2*3=9x^2)

3x(x-3)+1(x-3)=0

3x+1=0

x-3=0 here x=-1/3 or 3                                                              

Step-by-step explanation:

Answered by Anonymous
2

Given :-

3x² - 8x - 3 = 0

We can solve these type of equations using splitting the middle term method.

Steps to follow for splitting the middle term :-

  • Multiply the coefficient of the first and last term.

  • Find the pairs of multiples.

  • Choose one pair which makes the coefficient of the middle term either by addition or subtraction. use trial and error method.

Here, 3 × 3 = 9

Also 9 × 1 = 9 and 9 - 1 = 8 (coefficient of the middle term)

➡ 3x² - (9x - x) - 3 = 0

➡ 3x² - 9x + x - 3 = 0

➡ 3x(x - 3) + (x - 3) = 0

➡ (x - 3) (3x + 1) Final answer

If you further want to find it's zeroes, then simply equate both the factors by 0.

x = 3 or x = -1/3

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