Question

solve the quadratic equation 8 x square + 2 X + 1 = 0​

Answer 1

8x^2-2x-1=0

8x^2-4x+2x-1=0

4x(2x-1)+1(2x-1)=0

(4x+1)(2x-1)=0

4X=-1 or 2x=1

X=-1/4 X=1/2

Answer 2

The solution of equation is $x=\frac{-1+2\sqrt{7}i}{8},\frac{-1-2\sqrt{7}i}{8}$

Step-by-step explanation:

Given : Quadratic equation $8x^2+2x+1=0$

To find : Solve the quadratic equation ?

Solution :

The solution of the equation $ax^2+bx+c=0$ is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing,  $8x^2+2x+1=0$

Here, a=8 , b=2 and c=1

Substitute the value in the formula,

$x=\frac{-2\pm\sqrt{2^2-4(8)(1)}}{2(8)}$

$x=\frac{-2\pm\sqrt{4-32}}{16}$

$x=\frac{-2\pm\sqrt{-28}}{16}$

$x=\frac{-2+\sqrt{28}i}{16},\frac{-2-\sqrt{28}i}{16}$

$x=\frac{-1+2\sqrt{7}i}{8},\frac{-1-2\sqrt{7}i}{8}$

Therefore, the solution of equation is $x=\frac{-1+2\sqrt{7}i}{8},\frac{-1-2\sqrt{7}i}{8}$

#Learn more

Which constant must be added and subtracted to solve the quadratic equation 9x2 + 3/4x– 2 = 0 by the method of completing the square?

(A) 1/8 (B) 1/64 (C) 1/4 (D) 9/64

https://brainly.in/question/127550