Math, asked by aryanjat78211, 9 months ago

solve the quadratic equation 8x²-14x +3=0 when x€i and when x€q

Answers

Answered by Anonymous

6

Step-by-step explanation:

$8 {x}^{2} - 14x + 3 \\ \\ \\ 8 {x}^{2} - 12x - 2x + 3 \\ \\ 4x(2x - 3) - 1(2x - 3) \\ \\ (4x - 1)(2x - 3)$

Answered by ravisimsim

3

Step-by-step explanation:

$8 {x}^{2} - 14x + 3 \\ \\ 8 {x}^{2} - 12x - 2x + 3 \\ \\ 4x(2x - 3) - 1(2x - 3) \\ (4x - 1)(2x - 3)$

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