Math, asked by aryanjat78211, 9 months ago

solve the quadratic equation 8x²-14x +3=0 when x€i and when x€q

Answers

Answered by Anonymous
6

Step-by-step explanation:

8 {x}^{2}  - 14x + 3 \\  \\  \\ 8 {x}^{2}  - 12x - 2x + 3 \\  \\ 4x(2x - 3) - 1(2x - 3) \\  \\ (4x - 1)(2x - 3)

Answered by ravisimsim
3

Step-by-step explanation:

8 {x}^{2}  - 14x + 3 \\  \\ 8 {x}^{2}  - 12x - 2x + 3 \\  \\ 4x(2x - 3) - 1(2x - 3) \\ (4x - 1)(2x - 3)

Similar questions