Question

Solve the quadratic equation :

9x + 1/x = 6

Answer 1

Add 11 to both sides.

9x=6+19x=6+1

2 Simplify  6+16+1  to  77.

9x=79x=7

3 Divide both sides by 99.

x=\frac{7}{9}x=

​9

​

​7

​​  

Done

Answer 2

Answer:

1/3, 1/3

Step-by-step explanation:

9x + 1/x = 6

Therefore 9$x^{2}$ + 1 = 6x

or 9$x^{2}$ - 6x + 1 = 0

which is of the form a$x^{2}$ + bx + c = 0

Where a = 9, b = -6 and c = 1

The roots are = $\frac{-b + \sqrt{b^{2} - 4ac } }{2a}$ and $\frac{-b - \sqrt{b^{2} - 4ac } }{2a}$

$\frac{-(-6) + \sqrt{(-6)^{2} - (4*9 * 1) } }{2*9}$ and $\frac{-(-6) - \sqrt{(-6)^{2} - (4*9 * 1) } }{2*9}$

Therefore the roots are 6/18, 6/18 = 1/3, 1/3