Math, asked by nilangpok, 9 months ago

solve the quadratic equation ax²+bx+c=0 by method of completing the perfect square​

Answers

Answered by Anonymous
6

Answer:

ax2+bx+c=0  Multiply by 4a to get

4a2x2+4abx+4ac=0 Compete the square as

(2ax+b)2=4a2x2+4abx+b2 so that

 

4a2x2+4abx+4ac=(2ax+b)2-b2+4ac=0

(2ax+b)2=b2-4ac

2ax+b=±√(b2-4ac)

2ax=-b±√(b2-4ac)

x=(-b±√(b2-4ac))/(2a)

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