solve the quadratic equation ax²+bx+c=0 by method of completing the perfect square
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ax2+bx+c=0 Multiply by 4a to get
4a2x2+4abx+4ac=0 Compete the square as
(2ax+b)2=4a2x2+4abx+b2 so that
4a2x2+4abx+4ac=(2ax+b)2-b2+4ac=0
(2ax+b)2=b2-4ac
2ax+b=±√(b2-4ac)
2ax=-b±√(b2-4ac)
x=(-b±√(b2-4ac))/(2a)
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