Question

solve the quadratic equation by factorisation method √3x+11x+6√3=0​

write an appropriate and explained answer, please don't give irrelevant answers.
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Answer 1

$\rm √3x+11x+6√3=0$

$\begin{gathered}\rm \sqrt{3} x^{2} + 9x + 2x + 6 \sqrt{3} = 0 \\ \end{gathered}$

$\begin{gathered}\rm \sqrt{3x} (x + 3 \sqrt{3} ) + 2(x + 3 \sqrt{3} ) = 0 \\ \end{gathered}$

$\begin{gathered}\rm (x + 3 \sqrt{3} )( \sqrt{3} x + 2) = 0 \\ \end{gathered}$

$\begin{gathered}\rm x + 3 \sqrt{3} = 0 \\ \end{gathered}$

OR

$\rm \sqrt{3x} + 2 = 0$

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Answer 2

Answer:

$</p><p>\huge\mathfrak\blue{✰Answer}$

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$⟹ \sqrt{3x {}^{2} } + 11x + 6 \sqrt{3 = 0} \\ ⟹ \sqrt{3x {}^{2} } + 9x + 2x + 6 \sqrt{3} = 0 \\ ⟹ \sqrt{3x} (x + 3 \sqrt{3) } + 2(x + 3 \sqrt{3} ) = 0 \\ ⟹(x + 3 \sqrt{3} )( \sqrt{3} x + 2) = 0 \\ ⟹ \: x + 3 \sqrt{3} = 0 \\ or \sqrt{3} x + 2 = 0 \\ x \: = - 3 \sqrt{3} \\ or \: x \: = \frac{ - 2}{ \sqrt{3} }$

Hope it helps uhh