Question

solve the quadratic equation by the method of completing the square

Answer 1

Hey !!!

I've solved it
I'm attaching pics
Hope this helps

Answer 2

The answer is given below :

Now, the given equation is

$4 {x}^{2} + 4 \sqrt{3} x + 3 = 0 \\ \\ or, \: \: {(2x)}^{2} + 2 \times 2x \times \sqrt{3} + {( \sqrt{3}) }^{2} = 0 \\ \\ or,\: \:{(2x + \sqrt{3} )}^{2} = 0$

So,

$Either\:\:2x + \sqrt{3} = 0 \: \: or, \: 2x + \sqrt{3} = 0$

Therefore, the required solution is

$x = - \frac{ \sqrt{3} }{2}, \: \: - \frac{ \sqrt{3} }{2}$

Thank you for your question.