Math, asked by WeningNM7172, 8 months ago

Solve the quadratic equation D. −x²+ 7x − 10 = 0

Answers

Answered by sanikadamdoo36
11

Answer:

x=5 or X=2

Step-by-step explanation:

–x²+7x-10=0

By splitting the middle term,

=>–x²+5x+2x–10=0

=>–x(x-5)+2(x–5)=0

=>(x-5)(–x+2)=0

=>x-5=0 or –x+2=0

=>x=5 or X=2

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Answered by MrChauhan96
15

\bf\purple{\underline{\boxed{Question}}}

\:

Solve this by Quadratic formula

\rm{\ -x^{2}+7x-10}

\:

\bf\purple{\underline{\boxed{Solution}}}

\:

\tt{-x^{2}+7x-10\:=\:0}

\tt{Taking\:(-)\:common\:,}

\tt{x^{2}-7x+10\:=\:0}

\:

\small\tt{where\:\:,}

\small\tt{a\:=\:1}

\small\tt{b\:=\:7}

\small\tt{c\:=\:10}

\:

\small\tt{using\: formula}\\{\small\tt{D\:=\:b^{2}-4ac}}

\:

\small\tt{\:=\:7^{2}-4\times1\times10}

\small\tt{\:=\:49\:-\:40}

\small\tt{D\:=\: 9}

\:

\rm{\ x^{2}-7x+10}

\rm{x\:=\:\frac{-b±\sqrt{ \ b^{2}-4ac}}{2a}}

\rm{x\:=\:\frac{-(-7)±\sqrt{ 9}}{2\times 1}}

\rm{x\:=\:\frac{+7±\sqrt{ 9}}{2}}

\rm{x\:=\:\frac{7±3}{2}}

\:

\small\tt{There\:are\:2\:possible\:values}

\:

\small\tt{1)\:\:Postive\:}

\tt{x\:=\:\frac{7+3}{2}}

\tt{x\:=\:{\cancel\frac{10}{2}}}

\tt{x\:=\:5}

\:

\small\tt{2)\:\:Negetive\:}

\tt{x\:=\:\frac{7-3}{2}}

\tt{x\:=\:{\cancel\frac{4}{2}}}

\tt{x\:=\:2}

\:

\bf\purple{\underline{\boxed{Thanks}}}

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