Question

Solve the quadratic equation for x:
4√3x square+5x+2√3=0.

Answer 1

$4 \sqrt{3} {x}^{2} + 5x + 2 \sqrt{3} = 0 \\ \\ x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x = \frac{ - 5 + - \sqrt{25 - 4 \times 4 \sqrt{3 }\times 2 \sqrt{3} } }{2 \times 4 \sqrt{3} } \\ \\ x = \frac{ - 5 + - \sqrt{25 - 96} }{8 \sqrt{3} } \\ \\ = \frac{ - 5 + - \sqrt{71} }{8 \sqrt{3} }$