Math, asked by nonusingla4196, 1 year ago

Solve the quadratic equation formula for x square - 5 x minus 3 is equal to zero

Answers

Answered by attinderpaul55225
1

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given \: that \\  {x}^{2}  - 5x - 3 = 0 \\ we \: know \: the \: equation \: of \: quadric \\ that \:  \\  =a  {x}^{2}  + bx + c \\ here \: we \: can \: compair \: \\   \\ the \: coefficint \: of :  {x}^{2}  = 1 \\  \\ the \: coefficient \: of : x = ( - 5) \\  \\ the \: last \: coefficient :  = ( - 3) \\  \\ now \: the \: formula \: of \: quadric \\   the \: equation \:  =  {x}^{2} - 5x - 3 = 0 \\ =  > x =  \frac{ - b \frac{ + }{} \sqrt{ {b}^{2}  - 4ac}  }{2 \times a}  \\  =  > x =  \frac{ - ( - 5) \frac{ + }{}  \sqrt{ { (- 5)}^{2}  - 4.1.( - 3)} }{2 \times 1}  \\  =  > x =  \frac{5 \frac{ + }{} \sqrt{25 + 12}  }{2}  \\  =  > x =  \frac{5 \frac{ + }{}  \sqrt{37} }{2}  \\ here \: we \: get \: two \: values \: like \\ x =  \frac{5 +  \sqrt{37} }{2}  \\  =  > x =  \frac{5  -  \sqrt{37} }{2}

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✨✨hope it helps✨✨

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