Question

solve the quadratic equation: n² + 201n - 5400 = 0

Answer 1

n²+201n-5400=0
or,n²+225n-24n-5400=0
or,n(n+225)-24(n+225)=0
or,(n+225)(n-24)=0
either n+225=0 or n-24=0
either n=-225 or n=24
Ans:The roots of the equation are -225 and 24 which are the values of n.

Answer 2

n² + 201 n - 5400  = 0

   n = [ - 201 + - √(201² +4* 5400) ] / 2
     = [ -201  + - √62001 ] / 2 
     n  = [ -201 + -  249 ] /2
         = +24  or  - 225

so the factors are :  (n + 225) (n - 24)   of the quadratic polynomial.