solve the quadratic equation = p^2+8p=65
Answers
Answered by
1
Step-by-step explanation:
Bro it's really simple.
See... p^2 + 8p = 65.
so, we can use the "Sreedhacharya Formula":-
So, p= (-8 +- √(8)^2 - 4(1)(-65))/2(1)
=( -8 +- √324)/2
and now u can solve it further..It's pretty easy..
And yes...Note down this formula and Memorize it cuz it is really helpful Grade 10 onwards..
Sreedhacharya Formula:-
if Quadratic Equation is ax^2 + bx + c= 0,
then, x = [-b +- (√b^2 - 4ac)]/2a
..umm...Write the eqn in ur book..so u can understand claerly...
...Plzz mark me as Brainliest!!
Answered by
1
Answer:
-5,13
Step-by-step explanation:
p^2+8p-65=0
p^2+5p-13p-65=0
p(p+5)-13(p+5)=9
(p+5)(p-13)=0
p+5=0. p=-5
p-13=0. p=13
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