Question

Solve the quadratic equation
$(9x { {}^{2} }) {}^{2} - 148 x{}^{2} + 64 = 0$
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Answer 1

Answer:

hii mate hope my answer finds u in the pink of your health---

Step-by-step explanation:

9x^4-148x^2+64=0

64-148x^2+9x^4=0

(4-9x^2)(16-1x^2)=0

(2+3x)(2-3x)(16-x^2)=0

(4+x)(4-x)(2+3x)(2-3x)=0

hope this helps u

be happy

keep smiling

Answer 2

Hello Mate,

9x^4-148x^2+64=0

64-148x^2+9x^4=0

(4-9x^2)(16-1x^2)=

(2+3x)(2-3x)(16-x^2)=0

(4+x)(4-x)(2+3x)(2-3x)=0

Hope this helps you