Question

solve the quadratic equation using factorization y^2-4y+3=0

Answer 1

Answer:

y²-4y+3=0

y²-3y-y+3=0

y(y-3)-1(y-3)=0

(y-1)(y-3)=0

y=1 and y=3

hope it helps you....✌✌

Answer 2

Answer:

y²-4y+3=0

y²-y-3y+3=0

y(y-1)-3(y-1)=0

(y-1)(y-3)

there fore y = 1,3