Math, asked by iittssmmee89, 9 months ago

Solve the quadratic equation:

x^2 +3x-20=0​

Answers

Answered by mdibu03
1
HEY HERE IS YOUR ANSWER

STEP BY STEP EXPLANATION.....


QUADRATIC EQUATION FORMULA

 - b +  or -  \sqrt({ {b}^{2} }  - 4ac) \div 2a
so

 {x}^{2}  + 3x - 20
 a = 1 \\ b = 3 \\ c =  - 20 \\

( - 3  \frac{ + }{ - }  \sqrt{( {3}^{2} }  - 4(1)( - 20)) \div 2(1)
( - 3 \frac{ + }{ - }  \sqrt({9}   + 80)) \div 2

 (- 3 \frac{ + }{ - }  \sqrt{89} ) \div 2 \\  = ( - 3 +  \sqrt{89} ) \div 2 \:  \: or \:  \:  (- 3 -  \sqrt{89} ) \div 2
STEP BY STEP EXPLANATION

MARK AS BRAINLIEST
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