Math, asked by angal1234, 9 months ago


3 {x}^{2}  + 2x  - 5 = 0
solve the equation​

Answers

Answered by Anonymous
29

Answer :-

\sf 3x^2 + 2x - 5 = 0

By using middle term splitting -

\sf 3x^2 + 5x - 3x - 5 = 0

\sf x(3x + 5) -1(3x + 5) = 0

\sf (x - 1)(3x+5) = 0

Either ( x - 1 ) can be zero or ( 3x + 5 ) can be zero -

x - 1 = 0

x = 1

3x + 5 = 0

3x = -5

x = -5/3

\sf x = 1 , \frac{-5}{3}

Answered by civilengi4564
1

answer is same

Answer :-

\sf 3x^2 + 2x - 5 = 03x2+2x−5=0

By using middle term splitting -

\sf 3x^2 + 5x - 3x - 5 = 03x2+5x−3x−5=0

\sf x(3x + 5) -1(3x + 5) = 0x(3x+5)−1(3x+5)=0

\sf (x - 1)(3x+5) = 0(x−1)(3x+5)=0

Either ( x - 1 ) can be zero or ( 3x + 5 ) can be zero -

x - 1 = 0

x = 1

3x + 5 = 0

3x = -5

x = -5/3

\sf x = 1 , \frac{-5}{3}x=1,3−5

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