Question

$3 {x}^{2} + 2x - 5 = 0$
solve the equation​

Answer 1

Answer :-

$\sf 3x^2 + 2x - 5 = 0$

By using middle term splitting -

$\sf 3x^2 + 5x - 3x - 5 = 0$

$\sf x(3x + 5) -1(3x + 5) = 0$

$\sf (x - 1)(3x+5) = 0$

Either ( x - 1 ) can be zero or ( 3x + 5 ) can be zero -

x - 1 = 0

x = 1

3x + 5 = 0

3x = -5

x = -5/3

$\sf x = 1 , \frac{-5}{3}$

Answer 2

answer is same

Answer :-

\sf 3x^2 + 2x - 5 = 03x2+2x−5=0

By using middle term splitting -

\sf 3x^2 + 5x - 3x - 5 = 03x2+5x−3x−5=0

\sf x(3x + 5) -1(3x + 5) = 0x(3x+5)−1(3x+5)=0

\sf (x - 1)(3x+5) = 0(x−1)(3x+5)=0

Either ( x - 1 ) can be zero or ( 3x + 5 ) can be zero -

x - 1 = 0

x = 1

3x + 5 = 0

3x = -5

x = -5/3

\sf x = 1 , \frac{-5}{3}x=1,3−5