solve the quadratic equation (x2-1)2-5(x-1)-6=0
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Answer:
=> (x - 1)² - 5(x - 1) - 6 = 0
=> x² + 1 - 2x - 5x - 1 - 6 = 0
=> x² - 7x - 6 = 0
=> x² - 6x - x - 6 = 0
=> x(x - 6) - 1(x - 6) = 0
=> (x - 1)(x - 6) = 0
=> x = 1 or, x = 6
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