Math, asked by gholk97, 11 months ago

solve the quadratic equation (x2-1)2-5(x-1)-6=0​

Answers

Answered by Anonymous
23

HeYa❤️...

Correct Question

(x {}^{2}  - 1) {}^{2}  - 5(x - 1) - 6 = 0

Solution

given  = >   \: (x {}^{2}  - 1) {}^{2}  - 5(x - 1) - 6 =   0 \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = >  x {}^{2}  - 2x + 1 - 5x + 5 - 6 =   0 \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \: = >  x {}^{2}  - 7x + 6 - 6 = 0 \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \: = >  x {}^{2}  - 7x = 0 \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  = >  x(x - 7) = 0 \\  \\   \:  \:  \:  \:  \:  \:  \:  \:  \: => x = 0 \: or \: 7

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Answered by itzNarUto
5

Answer:

=> (x - 1)² - 5(x - 1) - 6 = 0

=> x² + 1 - 2x - 5x - 1 - 6 = 0

=> x² - 7x - 6 = 0

=> x² - 6x - x - 6 = 0

=> x(x - 6) - 1(x - 6) = 0

=> (x - 1)(x - 6) = 0

=> x = 1 or, x = 6

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