Question

solve the quadratic equation x2-13x +30=0 by factorisation method

Answer 1

x² -13x + 30 = 0

=> To solve by middle splitting term we multiply the constant and coefficient of x²

So, here coefficient of x² is 1 and constant term is 30

Now we have to find LCM of 30

LCM = 2× 3 × 5

Now we have either by subtracting or by adding we have to get -13 as middle one.

so, we can do it like :+


x² -10x -3x +30 = 0

x (x -10 ) -3 ( x -10) =0

(x -3 ) ( x - 10 ) =0

Answer 2

HELLO DEAR,


X²-13X+30=0


NOW ,

X² -10X -3X +30=0

X(X-10) +3(X-10) =0

(X-10) (X+4)=0

THEN,

X=10 &X=-4


I HOPE ITS HELP YOU DEAR,
THANKS