Question

Solve the quadratic equation : (x2- 4x -- 12 = 0)
(a) (x-6), (x+2)
(b) (x+6), (x-2)
(c) (x+3)(x-4)
(d) None of these​

Answer 1

Answer:

$:\implies$(x + 3)(x - 4)

hope it helps uh :)

Answer 2

x2-4x-12=0

x2-6x+2x-12=0

x(x-6)+2(x-6)

(x-6)(x+2)