Question

Solve the quadratic equations: (2X-3)(3X+1)=0
4X²+5X=0

Answer 1

Answer:

4X^2+5X=0

X(4X+5) =0

X=0 or X=-5/4

(2X-3) (3X+1) =0

6X^2-7X-3=0

D=(-7) ^2-4*6*(-3)

=49+72

=121

now,

X=7+√121/2*6 or X=7-√121/2*6

=7+11/12 or =7-11/12

=18/12 or =-4/12

=3/2 or=-1/3