Solve the quadratic polynomial p(x)=x^2-x-12 and also find it's zeroes?
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Answer:
x²-x-12 =0
x²-(4x-3x)-12
x²-4x+3x-12 =0
x(x-4) + 3(x-4) =0
(x-4)(x+3) =0
zeroes are 4 and -3
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