Question

Solve the ques by substitution method...

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

x = 3 and y = 1

Step-by-step explanation:

Solving Equation (i)

$2x - \frac{3}{y} = 9$

Multiplying Both sides by y

$2xy - 3 = 9y$

$2xy - 9y - 3 = 0$

$y(2x - 9) - 3 = 0$

$y(2x - 9) = 3$

$y = \frac{3}{2x - 9}$

Put Value of y in equation (ii)

$3x + \frac{7}{y} = 2$

$3xy + 7 = 2y$

$3x( \frac{3}{2x - 9} ) + 7 = 2( \frac{3}{2x - 9} )$

$\frac{9x}{2x - 9} + 7 = \frac{6}{2x - 9}$

Multiplying both sides by 2x-9

$9x + 7(2x - 9) = 6$

$9x + 14x - 63 = 6$

$23x = 6 + 63$

$x = \frac{69}{23}$

$x = 3$

Put x = 3 in equation (i)

$2x - \frac{3}{y} = 9$

$2xy - 3 = 9y$

$2 \times 3 \times y - 3 = 9y$

$6y - 3 - 9y = 0$

$- 3y - 3 = 0$

$y = \frac{3}{3}$

$y = 1$

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