Math, asked by 000956, 3 months ago

solve the ques given below and answer correct i will mark brainliest and its urgent

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Answered by ridhya77677
1

Answer:

 =  {( {x}^{a - b} })^{a + b}  \times  { ({x}^{b - c} })^{b + c}  \times  { ({x}^{c - a} })^{ c + a}  \\  =  {x}^{( {a}^{2}  -  { {b}^{2} })}  \times  {x}^{ ({b}^{2}  -  {c}^{2}) }   \times  {x}^{ ({c}^{2}  -  {a}^{2}) }  \\  =  {x}^{ {a}^{2} -  {b}^{2}  +  {b}^{2}   -  {c}^{2}  +  {c}^{2} -  {a}^{2}  }  \\ =   {x}^{0}  \\  = 1

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