solve the quest 5 of differential equation
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(y-x)dy=(y2-x2)dx
dy/dx=(y+x)(y-x)/(y-x)
dy/dx=(y+x)
now from given equation y+x=-1
put in it ..
and if differentiate the y+x+1 then we get the same equation ,here value of dy/dx is same so it is its solution....if u are satisfied with my ans thn mark me as brainlist.....
dy/dx=(y+x)(y-x)/(y-x)
dy/dx=(y+x)
now from given equation y+x=-1
put in it ..
and if differentiate the y+x+1 then we get the same equation ,here value of dy/dx is same so it is its solution....if u are satisfied with my ans thn mark me as brainlist.....
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