Question

solve the question asked above

Answer 1

That's the answer of your problem.

Answer 2

Let AB be the line joining points A(1,2) and (5,-6).

Hence the midpoint of the line AB is:

= > (x1 + x2/2, y1 + y2/2)

= > (1 + 5/2, 2 - 6/2)

= > (3, -2).

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Now,

The slope of the line is:

= > m1 = (y2 - y1)/(x2 - x1)

= > m1 = (-6 - 2)/(5 - 1)

= > m1 = (-8)/(4)

= > m1 = -2.

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The slope of the perpendicular is:

= > m2 = -1/slope of the line

= > m2 = -1/-2

= > m2 = 1/2.

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Now,

The equation of the line passing through (3,-2) and slope (1/2) is:

= > (y + 2) = (1/2)(x - 3)

= > 2(y + 2) = (x - 3)

= > 2y + 4 = x - 3

= > 2y + 4 - x + 3 = 0

= > x - 2y - 7 = 0.

Hope this helps!