solve the question by substitution method...
3x-y= 4
9x-3y= 9
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hi,
the pb goes like this....
3x-y =3 equ..1
9x-3x=9 equ...2
from 1,we get
y=3x-3 equ..3
sub. this value in equ 2 , we get
9x-3(3x-3)=9
9x-9x+9=9 +9 and -9 gets cancelled...
9=9
this is always true
hence,the given pairs of the equations has infinite possible solutions and the relation between these variables can be given by y=3x-3 ....
∴ 1 of its possible solutions is x=1 and y=0
hope my ans helps u..
the pb goes like this....
3x-y =3 equ..1
9x-3x=9 equ...2
from 1,we get
y=3x-3 equ..3
sub. this value in equ 2 , we get
9x-3(3x-3)=9
9x-9x+9=9 +9 and -9 gets cancelled...
9=9
this is always true
hence,the given pairs of the equations has infinite possible solutions and the relation between these variables can be given by y=3x-3 ....
∴ 1 of its possible solutions is x=1 and y=0
hope my ans helps u..
thanx buddy...
my pleasure
^_^
how can u say ??
then what is the correct 1.....??
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