Question

Solve the question by substitution method.Find X and Y​

Answer 1

Given:

$\frac{x}{2} +y = 0.8\\\\\frac{7}{x+\frac{7}{2}} = 5$

To prove:

Find x and y by substitution method.

Solution:

$\rightarrow \frac{x}{2} +y = 0.8....(i) \\\\ \rightarrow \frac{7}{x+\frac{7}{2}} = 5...(ii)$

Solve equation (ii) and put the value of equation (a) in equation (i):

$\rightarrow \bold {\frac{7}{x+\frac{y}{2}} = 5}\\\\\rightarrow \frac{7}{5} = x+\frac{y}{2} \\\\ \rightarrow \frac{7}{5} = \frac{2x+y}{2} \\\\\rightarrow \frac{14}{5} = 2x+y \\\\\rightarrow 2x+y = 2.8\\\\\rightarrow y = 2.8-2x ......(a)$

Equation (i)

$\bold {\rightarrow \frac{x}{2}+y =0.8}\\\\\rightarrow \frac{x+2y}{2} =0.8\\\\\rightarrow x+2y =1.6$

putting the value:

$\rightarrow x+2(2.8-2x) =1.6\\\\\rightarrow x+ 5.6-4x =1.6\\\\\rightarrow 5.6 -1.6= 3x\\\\\rightarrow 4.0= 3x\\\\\rightarrow x= \frac{4}{3}\\\\\rightarrow x= 1.33$

put the value of x in equation a:

equation:

$\rightarrow \bold{y = 2.8-2x}\\\\\rightarrow y = 2.8-2(1.33)\\\\\rightarrow y = 2.8-2.66\\\\\rightarrow y = 0.14$

The final value of x and y is  "1.33" and "0.14".